Find the sum of 10terms of an ap whose nth term is 1-4
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Answer:
Step-by-step explanation:
an=4n−1
a1=a×1−1=3
a2=4×2−1=7
a3=4×3−1=11
d=11−7=7−3=4
a=3
n=20
Sn=S20=n2[2a+(n−1)d]
S20=202[2×3−(20−1)×4]
S20=10[6+19×4]
S20=10×[6+76]
=10×82=820
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