find the sum of 10th term of 5 + 8 + 11
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Answer:
Step-by-step explanation:
AP= 5,8,11...
Here's=5,d=8-5=3
Sum of nth term= n/2[2a+(n-1)d
Sum of 10th term= 10/2[2×5+(10-1)3]
=5[10+9(3)]
=5(10+27)
=5×37
=185
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