find the sum of 11+13+15+... using the property that the sum of the first n odd natural numbers is n2
Attachments:
Answers
Answered by
0
Answer:
n²-25
Step-by-step explanation:
11+13+15+... up to n terms
= (1+3+5+7+... n terms) - (1+3+5+7+9)
= n² - 5²
= n² - 25
Similar questions