find the sum of 11^3 + 12^3+......+25^3
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Hey user !!
Here's the answer you are looking for
Please see the attachment for your answer.
ALTERNATIVE PROCESS (Using special series)
11³ + 12³ + .... + 25³
= (1³+2³+...+25³) - (1³+2³+...+10³)
We know,
1³ + 2³ + .... + n³
= ∑n³ = [n(n+1)/2]²
Here, we get
∑25³ - ∑10³
= [25(26)/2]² - [10(11)/2]²
After calculating (as shown in the attachment), answer will be 102600.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Please see the attachment for your answer.
ALTERNATIVE PROCESS (Using special series)
11³ + 12³ + .... + 25³
= (1³+2³+...+25³) - (1³+2³+...+10³)
We know,
1³ + 2³ + .... + n³
= ∑n³ = [n(n+1)/2]²
Here, we get
∑25³ - ∑10³
= [25(26)/2]² - [10(11)/2]²
After calculating (as shown in the attachment), answer will be 102600.
★★ HOPE THAT HELPS ☺️ ★★
Attachments:
sumofseries:
can u solve it using the formula of special series
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