Find the sum of 11 term of the Ap whose middle term is 30
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If there are 11 term, then the middle term will be 6
i.e a₆=30
= a+5d=30 (1)
= S₁₁= 11/2 (2a+10d)
= S₁₁= 11/2 × 2(a+5d)
= S₁₁= 11 × a+5d
= S₁₁= 11 × 30 (using 1)
= S₁₁= 330
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