Find the sum of 11 terms of AP whose middle term is 30
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HERE,
n=11
(a1+a11)/2 = 30
=(a1=a11) = 60
sum of ap = n(a1+ a11)/2
= 11*60/2
= 330
n=11
(a1+a11)/2 = 30
=(a1=a11) = 60
sum of ap = n(a1+ a11)/2
= 11*60/2
= 330
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