Question

Find the sum of 12 terms of an AP whose nth term is given by an=3n+4
(a) 262
(b) 272
(c) 282
(d) 292

Answer 1

Answer:

c)282

Step-by-step explanation:

this is the right answer

Answer 2

Answer:

Hope my answer helps you :-)

Step-by-step explanation:

a¹=3(1)+4=7

a²=3(2)+4=10

a³= 3(3)+4=13

d is 3

Sum of first 12 terms of an A. P .

Sum of first 12 terms of an A. P .is

Sum of first 12 terms of an A. P .is:: 12/2(7+7+(12-1)3)

Sum of first 12 terms of an A. P .is:: 12/2(7+7+(12-1)3):: 6(14+33)

Sum of first 12 terms of an A. P .is:: 12/2(7+7+(12-1)3):: 6(14+33):: 6*47

Sum of first 12 terms of an A. P .is:: 12/2(7+7+(12-1)3):: 6(14+33):: 6*47:: 282

Sum of first 12 terms of an A. P .is:: 12/2(7+7+(12-1)3):: 6(14+33):: 6*47:: 282Hence your answer is C

Sum of first 12 terms of an A. P .is:: 12/2(7+7+(12-1)3):: 6(14+33):: 6*47:: 282Hence your answer is CMark me as the brainliest