Find the sum of 12ab + 2bc + 4cd – 3 and - 2ab + 3cd- 2 and 5ab - 7bc + 12.
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Answer:
Find sum of : 8ab−5ab,3ab,−ab.
⇒8ab+(−5ab)+(3ab)+(−ab)
=(8−5+3−1)ab
=5ab
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