Question

find the sum of 14 terms of the series 11+ 13+15+17​

Answer 1

Answer:

336

Step-by-step explanation:

a= 11

d = 13 - 11 =2

no of terms = 14

sum of terms =

$\frac{n}{2}[2a + (n-1) d\\\\Substituting,\\\\\frac{14}{2}[22+(14-1)2]\\\\7[22+26]\\\\7 X 48 = 336$