find the sum of 15 terms of an arithmetic progression 2, 7, 12.....using formula
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a=2 , d=a2 - a1=7-2=5
S=n/2 [2a+(n-1)d]
S=15/2 [2×2+(15-1)5]
S=15/2 [4+14×5]
S=15/2[4+70]
S=15/2×74
S=555
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