find the sum of 15 terms of the AP 1/2,1/2,1/2,........
Answers
Answered by
3
Hi Friend !!!
Here is ur answer !!!
a = 1/2
d = 1/2 - 1/2
= 0
n = 15
Sn = n/2 (2a+(n-1)d)
= 15/2 (2(1/2) + 14(0))
= 15/2 (1+0)
= 15/2 (1)
= 15/2
Hope it helps u :-)
Here is ur answer !!!
a = 1/2
d = 1/2 - 1/2
= 0
n = 15
Sn = n/2 (2a+(n-1)d)
= 15/2 (2(1/2) + 14(0))
= 15/2 (1+0)
= 15/2 (1)
= 15/2
Hope it helps u :-)
Answered by
3
Common difference = 1/2 - 1/2 = 0
first term = 1/2
Last term = 15th term = a + 14(d)
= 1/2 + 14(0)
= 1/2 + 0
= 1/2
=====================================
![S_{n} = \frac{n}{2} [First term + last term] S_{n} = \frac{n}{2} [First term + last term]](https://tex.z-dn.net/?f=+S_%7Bn%7D++%3D++%5Cfrac%7Bn%7D%7B2%7D++%5BFirst+term+%2B+last+term%5D)
Here,
![S_{15} = \frac{15}{2} [1/2 + 1/2] S_{15} = \frac{15}{2} [1/2 + 1/2]](https://tex.z-dn.net/?f=+S_%7B15%7D++%3D++%5Cfrac%7B15%7D%7B2%7D++%5B1%2F2+%2B+1%2F2%5D)
![S_{15} = \frac{15}{2}[1] S_{15} = \frac{15}{2}[1]](https://tex.z-dn.net/?f=+S_%7B15%7D++%3D++%5Cfrac%7B15%7D%7B2%7D%5B1%5D)
Sum of 15 terms = 15/2 = 7.5
i hope this will help you
(-:
first term = 1/2
Last term = 15th term = a + 14(d)
= 1/2 + 14(0)
= 1/2 + 0
= 1/2
=====================================
Here,
Sum of 15 terms = 15/2 = 7.5
i hope this will help you
(-:
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