Find the sum of 15 terms of the list of numbers whose nth term is given by an=3+4n
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hey mate here is ur answer
a1=3+4=7
a2=3+8=11
a3=3+12=15
..
a=7 , d=4
sn=n/2[2a+(n-1)d]
s15=15/2[14+14×4]
=15/2[70]
=15×35
=525.
hope it helps.
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