Find the sum
of 16 torm of Ap. 2,5,8,11
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Step-by-step explanation:
Given AP : 2,5,8,11...
First term (a)=2
Common difference (d)=5-2=3
we know that Sn=n/2[2a+(n-1)d]
we have n=16
S16=16/2[2(2)+(16-1)(3)]
=>8[4+15×3]
=>8(4+45)
=>8×49
S16 =>392
sum of 16 terms of the given A P =392
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