Math, asked by ps8343112, 1 month ago

Find the sum of 17 consecutive cubical numbers starting from 3.

Answers

Answered by parikshit17

0

Answer:

1=1=1

3

,

3+5=8=2

3

,

7+9+11=27=3

3

,

13+15+17+19=64=4

3

,

21+23+25+27+29=125=5

3

,

31+33+35+37+39+41=216=6

3

.

Therefore, the sum of odd consecutive cube number for 6

3

=216 must be 31+33+35+37+39+41.

Answered by shivkumaripradhanmen

0

Answer:

wrong

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