find the sum of 1st 15 multiples of 8
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Answered by
0
Step-by-step explanation:
8+16+24+32+40 : 120
thanks
Answered by
2
Sn=n/2(2a+(n-1)d)
S15 = 15/2(2×8+(15-1)8
= 15/2(16+(14)8)
= 15/2(16+112)
= 15/2 x 128
= 15 x 64
= 960
The sum of the first 15 multiples of 8 is 960.
Step-by-step explanation:
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