find the sum of 1st 18 terms of an AP whose nth term is 3-2n.
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Answered by
22
tn = 3-2n
t18 = a + (n-1) d
= a + 17d
t1 = a
S18 = n/2 ( 2a + (n-1) d )
= 9 (2a + 17d)
t18 = a + (n-1) d
= a + 17d
t1 = a
S18 = n/2 ( 2a + (n-1) d )
= 9 (2a + 17d)
kvj24:
no conditions are given
wait ?
Answers
1st= 3-2(1)= 1
2nd=3-2(2)= -1
3rd=3-2(3)= -3
therefore a=1 d=-2
Formula for sum of A.P = n/2{2a+(n-1)d}
18/2*(2-34) = -288
1st= 3-2(1)= 1
2nd=3-2(2)= -1
3rd=3-2(3)= -3
therefore a=1 d=-2
Formula for sum of A.P = n/2{2a+(n-1)d}
18/2*(2-34) = -288
see.it is possible
then r u testing our knowledge?????
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