Find the sum of 1st 50 natural numbers which divisible by 5
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Step-by-step explanation:
step 1 Address the formula, input parameters & values.
Input parameters & values:
The number series 5, 10, 15, 20, 25, 30, 35, 40, 45, . . . . , 250.
The first term a = 5
The common difference d = 5
Total number of terms n = 50
step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 50/2 x (5 + 250)
= (50 x 255)/ 2
= 12750/2
5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + . . . . + 250 = 6375
Therefore, 6375 is the sum of first 50 positive integers which are divisible by 5.
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