find the sum of 1st n natural number
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Natural number set is always in AP
So first term of it. a= 1
Common difference d= 1
nth term of it. an=1+(n-1)1=n
Sum of the series. Sn= n(a+l)/2
Where l is the nth term
Sn= n(1+n)/2
So first term of it. a= 1
Common difference d= 1
nth term of it. an=1+(n-1)1=n
Sum of the series. Sn= n(a+l)/2
Where l is the nth term
Sn= n(1+n)/2
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