find the sum of 1st n odd natural numbers
Answers
Answered by
2
Answer:
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Step-by-step explanation:
The sequence of first n odd numbers is
1,3,5,7.........n
This forms an A.P with a=1 and d=2
S=
2
n
{2a+(n−1)d}
⇒S=
2
n
{2(1)+(n−1)2}
⇒S=
2
n
(2n)
⇒S=n
2
Answered by
1
according to the odd number theorem, the sum of first n number is equal to the square of n
let's take an example
sum of first two number
1+3=2²
4=4
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