Find the sum of -2+2+(-2)+....... 73 times
Anonymous:
73 TIMES???!??!!!?!
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Answered by
3
the sum is -2.......bcoz the sum of first term and second term will be 0
sum of third and fourth term is also 0
and so on.....till the sum of 71 st term and 72nd term is also 0
now only 73st term is remaining
therefore the sum is -2
I hope this will help u ;)
sum of third and fourth term is also 0
and so on.....till the sum of 71 st term and 72nd term is also 0
now only 73st term is remaining
therefore the sum is -2
I hope this will help u ;)
Answered by
0
When you add a positive integer with its additive inverse, then the answer will always be 0 or the number itself. First write all the (-2)+2+(-2)+2.....and so on..........
As 73 is an odd number, the number of pairs (like (-2)+2) will be 36 with -2 left out. If you count till the 36th pair, then your answer is 0, but then one -2 is left out, so the answer will be -2.
HOPE YOU UNDERSTOOD THE CONCEPT I USED!
PLZ MARK MY ANSWER THE BRAINLIEST!
As 73 is an odd number, the number of pairs (like (-2)+2) will be 36 with -2 left out. If you count till the 36th pair, then your answer is 0, but then one -2 is left out, so the answer will be -2.
HOPE YOU UNDERSTOOD THE CONCEPT I USED!
PLZ MARK MY ANSWER THE BRAINLIEST!
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