find the sum of 2+4+6+........+200
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a = 2
d = 4-2=2
last term = a+(n-1)d
200 = 2 +(n-1)2
198/2= n-1
99+1 = n
100 = n
So, 200 is the 100th term.
Sum of 100 terms = n/2(a+l)
=> 100/2(2+200)
=>50×202
=>10100
Cheers!✌
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