Math, asked by rakhi9072, 6 months ago

find the sum of (2/5)-³+(4/5)-²+(3/2)-³.​

Answers

Answered by nityachhabra111
0

Answer: 2/3]² ÷ [4/5]³ × [3/5]² = 5[1/2]⁴

Step-by-step explanation:

[2/3]² ÷ [4/5]³ × [3/5]² = (2/3*2/3) ÷ (4/5×4/5×4/5) × (3/5×3/5) = 4/9 ÷ 64/125 × 9/25=5/16

5[1/2]⁴=

[1/2]⁴=1/2*1/2*1/2*1/2=1/16

5*1/16=5/16

5[1/2]⁴=5/16

Answered by SuhaniiAgarwal
0

Answer:

7553/432

Step-by-step explanation:

(2/5)^(-3) + (4/5)^(-2) + (3/2)^(-3)

When we Reciprocal the number, the sign of the power will change.

(5/2)³ + (5/4)² + (2/3)³

= 125/8 + 25/16 + 8/27

= 6750+675+128 /432

= 7553/432

Hope it helps you:)

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