find the sum of 20 terms 1,4,7,20 and so on
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Answer:
(2a+(n−1)d)
wheres
n
=sumofnterms
a=firstterm
d=difference
n=numberofterms
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=> 1st term (a) = 1
=> difference (d ) = (4-1)=(7-4)=3
=> Sum of 20 terms
2
20
((2×1)+(20−1)3)
=10(2+(19×3))
=10(2+57)=59×10
=
590
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