find the sum of 20 terms of an ap 3, 7, 11 and so on
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a20 = a + ( n- 1)× d
a20= 3 + [20 - 1]× 4
a20 = 3 + 76
a20= 79
sn = n÷2 (l + a)
sn = 20÷2 (79 + 3)
sn = 820
a20= 3 + [20 - 1]× 4
a20 = 3 + 76
a20= 79
sn = n÷2 (l + a)
sn = 20÷2 (79 + 3)
sn = 820
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