Find the sum of 20 terms of parallel series of 0,4,8,12
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Answer:
760
Step-by-step explanation:
S(n) -> Sum of n terms:
S(n) = n/2 [2a+(n-1) d]
here n=20
a=0
d=4
S(20) = 20/2 [2(0)+ (20-1)×4]
= 10× (19×4)
= 760
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