Find the sum of 20 terms of the AP 18, 16, 14
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0
Answer:
Step-by-step explanation:
n=20
a=18
d=16-18=-2
Sn=n/2(2a+(n-1)d)
Sn=20/2(2*18+(20-2)*(-2))
Sn=10(36-38)
Sn=10*(-2)
Sn=-20
Vikram5176:
How sum can be -20 how it can be negative
Answered by
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a= 18
d= 16-18=-2
n = 20
Sn= n/2(2a+(n-1)d)
= 20/2 (2*18+(20-2)*(-2))
= 10(36+(19)*(-2))
= 10(36-38)
= 10*(-2)
= -20
d= 16-18=-2
n = 20
Sn= n/2(2a+(n-1)d)
= 20/2 (2*18+(20-2)*(-2))
= 10(36+(19)*(-2))
= 10(36-38)
= 10*(-2)
= -20
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