find the sum of 21 terms of an ap whose middle term is 20.
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n=21
(a1 + a21)/2 = 20
=(a1 + a11)= 40
sum of ap =n(a1+a11)/2
=21*40/2
=840/2
= 420.
n=21
(a1 + a21)/2 = 20
=(a1 + a11)= 40
sum of ap =n(a1+a11)/2
=21*40/2
=840/2
= 420.
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