find the sum of 22nd term of Ap 8,3,-2
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Answered by
1
Answer:
a=8
d=3−8=−5
S22 = n/2 [2a+(n−1)d]
S22 = 22/2 [2a+21d]
S22 = 11[2(8)+21(−5)]
S22 = 11(−89)
=−979.
the sum of 22nd term of Ap is -979
hope it helps you...
Answered by
0
Step-by-step explanation:
first term is a=8
nth term in Ap is a+(n-1)d
22nd term is 8+(22-1)(-5) = 8+21×(-5) = -97
sum of 22 terms is n/2{2a+(n-1)d}
11(16+21×(-5)) = -979
-979 is the sum of 22 terms
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