find the sum of 25 divisible numbers of 5
Answers
Step-by-step explanation:
Given numbers 0,1,2,3,4,5. We need to find 5 digit numbers, since the numbers must be divisible by 25, the last 2 digits must be either 25,50
i). If last 2 digits are 2,5
The first can't be 0 so only 3 choices =
3
C
1
, remaining 2 places can be filled by the remaining 3 numbers in
3
P
2
ways.
Total =
3
C
1
×
3
P
2
=3×6=18
ii). If last 2 digits are 5,0
The first 3 digits can be filled by 4 numbers in
4
C
3
ways.
Total =
4
C
3
=24
⇒ Required =18+24
=42 numbers possible.
Hence, the answer is 42.
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The sum of all 4−digit even numbers that can be formed from the digits 1,2,3,4,5 (without repetition) is:
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The sum
26
C
6
+∑
r=0
5
21+r
C
5
is equal
n
C
6
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