Question

Find the sum of 25 terms of ap 1/9,2/9,3/9...........

Answer 1

Answer:

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25 / 9 =189/9

=21 answer

Step-by-step explanation:

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Answer 2

Given 1/9,2/9,3/9

a = 1/9 , d = 1/9

Sn = n/2 ( 2a + (n-1)d)

     =(25/2)(2/9 + 24( 1/9))

     = ($(\frac{25}{2})( \frac{2+24}{9} )= \frac{(25)(26)}{18}$

     = 25X13/9

     = 325/9

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