Find the sum of -2x²y², -1/3x²y², -1/6x²y², 4/3x²y²
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Answer:
-7x^2y^2/6
Step-by-step explanation:
-2x^2y^2+(-1/3x^2y^2)+(-1/6x^2y^2)+4/3x^2y^2
-2x^2y^2-1/3x^2y^2-1/6x^2y^2+4/3x^2y^2
-2x^2y^2+x^2y^2-1/6x^2y^2
-x^2y^2-1/6x^2y^2
(-6x^2y^2-1x^2y^2)/6
(-7x^2y^2)/6
Here's your answer
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