Math, asked by paraghq8231, 7 months ago

Find the sum of -2x²y², -1/3x²y², -1/6x²y², 4/3x²y²

Answers

Answered by khushiMohare625
1

Answer:

-7x^2y^2/6

Step-by-step explanation:

-2x^2y^2+(-1/3x^2y^2)+(-1/6x^2y^2)+4/3x^2y^2

-2x^2y^2-1/3x^2y^2-1/6x^2y^2+4/3x^2y^2

-2x^2y^2+x^2y^2-1/6x^2y^2

-x^2y^2-1/6x^2y^2

(-6x^2y^2-1x^2y^2)/6

(-7x^2y^2)/6

Here's your answer

Hope it's help u!!!!

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