Question

Find the sum of 3/13 + 1 5/26 + 2 7/39 and subtract it from 8

Answer 1

Step-by-step explanation:

Question 1:

Solve:

(i) 2 – 3/5 (ii) 4 + 7/8 (iii) 3/5 + 2/7 (iv) 9/11 – 4/15 (v) 7/10 + 2/5 + 3/2

(vi) 2 + 3 (vii) 8 - 3

Answer:

(i) 2 – 3/5 = 2/1 – 3/5

= (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5]

= (10 - 3)/5

= 7/5

= 1

(ii) 4 + 7/8 = 4/1 + 7/8

= (4 * 8 + 7)/8 [LCM (1, 8) = 8]

= (32 + 7)/8

= 39/8

= 4

(iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35]

= (21 + 10)/35

= 31/35

(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165]

= (135 - 44)/165

= 91/165

(v) 7/10 + 2/5 + 3/2 = (7 * 1 + 2 * 2 + 3 * 5)/10

= (7 + 4 + 15)/10

= 26/10 [26 and 10 are divided by 2]

= 13/5

= 2

(vi) 2 + 3 = 8/3 + 7/2

= (8 * 2 + 7 * 3)/6 [LCM (2, 3) = 6]

= (16 + 21)/6

= 37/6

= 6

Answer 2

Answer:

$\frac{3}{13} + 1\frac{5}{26} + 2 \frac{7}{39}$

as the LCM of 13 , 26 , 39 will be 78 so

$\frac{18 + 93 + 170}{78}$

= $\frac{281}{78}$

Now,

$\frac{281}{78} - 8$

= $\frac{624 - 281 }{78}$

= $\frac{343}{78}$

= $4\frac{31}{78}$

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