find the sum of 3+7+11+......25 terms
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Answered by
16
a=3,n=25,d=7-3=4
S₂₅=n/2(2a+(n-1)d)
S₂₅=25/2[2(3)+(25-1)4]
S₂₅=25/2(6+96)
S₂₅=25/2(102)
S₂₅=25(51)
S₂₅=1275.
S₂₅=n/2(2a+(n-1)d)
S₂₅=25/2[2(3)+(25-1)4]
S₂₅=25/2(6+96)
S₂₅=25/2(102)
S₂₅=25(51)
S₂₅=1275.
lohithanaidu:
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Answered by
6
Sn= n/2[ 2a+(n-1) d].......... Here a=3,,,,,, d= 7-3= 4..... and n= 25....
S25= 25/2[6+24×4]..................... S25= 25/2[6+ 96]............................. S25= 25/2[102]........ Now, 102 is cancelled fro. 2... 51 remains...... S25= 51×25............. S25= 1275
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