Find the sum of 3+7+11+... to 18 terms
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Answer:
3+7+11 21 is the right answer of the question
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Answer:
formula of sum of n numbers of AP = n/2 [2a + (n-1)d]
= 18/2 [2x3 + ( 18-1) x 4 ]
= 9 [6 + 68]
= 9 x 74
= 666
therefore, total sum of 3+7+11 up to 18 terms = 666
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