Question

find the sum of 3 consicutive which sums 200​

Answer 1

Let the numbers be x, x+1, x+2

Then

A.T.Q ;

x + x + 1 +x+2 = 200

3x + 3 = 200

3x=197

x=197/3

x=67 ans.

x+1=68 ans.

x+2=69 ans.

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Answer 2

Answer:

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• We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 200. Therefore, you can write the equation as follows:

• (X) + (X + 1) + (X + 2) = 200

• What three consecutive integers have a sum of 200?

• Three Consecutive Integers

• Here we will use algebra to find three consecutive integers whose sum is 200.
• We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 200.
• Therefore, you can write the equation as follows:

• (X) + (X + 1) + (X + 2) = 200

• Too solve for X, you first add the integers together and the X variables together.
• Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

• X + X + 1 + X + 2 = 200
• 3X + 3 = 200

• 3X + 3 - 3 = 200 - 3
• 3X = 197

• 3X/3 = 197/3
• X = 65 2/3

• Since 65 2/3 is not an integer, there is no true answer to this problem.
• However, there are three numbers that add up to 200.
• The first number is (65 2/3), the second number is (65 2/3) + 1, and the third number is (65 2/3) + 2.

• Therefore, we could make this the answer to "Three consecutive numbers that add up to 200 are:-

• 65 2/3 + 66 2/3 + 67 2/3 = 200.