Question

Find the sum of 3 digit nos from 100 to 150 which are divisible by 3​

Answer 1

The required numbers are :-

102, 105, ........, 147, 150,

This series firms an AP, with ,

First term, a = 102

Last term, l = 150

Common difference , d = 3

So,

l = a + (n-1)d

150 = 102 + 3(n-1)

3(n-1) = 48

n-1 = 16

n= 17

Sum = n ( a + l )/2

= 17(102+150)/2

= 17(252)/2

= 17×126

= 2142

Hope it may help you !!!!!

Answer 2

Answer:

Step-by-step explanation: 102 105 108 ...... 150

t1=102

d=3

Tn=150

S150=n/2 x 2a+n-1 x d

150/2 x2x102 + 150 -1 x 3

=15447

S150=15447

The sum of nos from 100 to 150 which are divisible by 3 are 15447