Find the sum of 3 digit numbers not divisible by 7.
Answers
Answer:
Sum of all three digit numbers which are not divisible by 7
= Sum of all three digit numbers – Sum of all three digit numbers which are divisible by 7
Sum of all three digit numbers
= 100 + 101 + 102 +...... + 999 [ The series is in A.P.]
Sum of all three digit numbers which are divisible by 7
= 105 + 112 + ..... + 994
Let 994 be the nth term of the given series.
∴ 994 = 105 + (n – 1) × 7
⇒ 7(n – 1) = 889
⇒ n – 1 = 127
⇒ n = 128
So, sum of all three digit numbers which are divisible by 7
∴ Sum of all three digit numbers which are not divisible by 7 = 494500 – 70336 = 424164
Step-by-step explanation:
sum of all three digit number which are not divisible by 7 (Sn)= sum of all three digit numbers(Sn1)-sum of all three digit numbers divisible by 7(Sn2)
sum of all three digit numbers,
100+101+102.....+999
but we have to find the value of n....
an = a+(n-1)d
999 = 100+(n-1)*1
999-100 = n-1
899+1 = n
900 = n
sum of all three digit numbers..{S1)
so we know that,
S1 = n/2(a+l)
S1 = 900/2(100+999)
S1 = 450*1099
S1 =494550
Now,sum of all three digit numbers divisible by 7....{S2}
105+112......+994
finding the value of n....
an =a+(n-1)d
994= 105+(n-1)*7
994-105=(n-1)7
889/7= n-1
127+1=n
128=n
now.....
S2 = n/2(a+l)
S2= 128/2(105+994)
S2=64(1099)
S2=70336
Now,sum of all three digit numbers not divisible by 7= sum of all three digit numbers- sum of all three digit numbers divisible by 7
or we can say
Sn= Sn1-Sn2
Sn=494550-70336
Sn=424214
Therefore,sum of all three digit numbers not divisible by 7 is 424214...
VERY IMPORTANT QUESTION