Question

Find the sum of 3 digits number each of which dividing by 5 reminder will be 3

Answer 1

103,108,113,.....,998
it is an AP
d=108-103=5
998=a+(n-1)d
103+(n-1)5=998
n-1=(998-103)/5=895/5
n=179+1=180
S=180/2(103+998)
=90×1101=99090