Question

find the sum of 30 terms of the AP: 1,4,7,10...

Answer 1

Solution is in the attachment

Answer 2

Heya!!Here is your answer friend ⤵⤵

⏪Given AP ,

1, 4 , 7, 10.......

$here \: a = 1 \: and \: \: d = 3 \\ sn = \frac{n}{2} (2a + (n - 1)d) \\ \\ s30 = > \frac{30}{2} (2 \times 1 + (30 - 1)3) \\ = > 15(2 + 29 \times 3) \\ = > 15(2 + 87) \\ = > 15 \times 89 = 1335$
Hope it helps you ✌✌☺