find the sum of 32terms of an ap whose 3rd term is 1 and 6th term is -11
Answers
Answered by
1
Answer:
third term =1---(a+2d)--------------1
6th term=-11-----(a+5d)--------------2
by eliminate
-3d=12
d=-4
put d=-4in 1
a+2×-4=1
a-8=1
a=9
sn=n/2(2a +(n-1)d)
sn=32/2(2×9+31×-4)
=16(18-124)
=16(106)
=1696
Answered by
0
Step-by-step explanation:
here comes the answer....
Attachments:
Similar questions