Math, asked by sangwanbanita, 1 year ago

find the sum of 32terms of an ap whose 3rd term is 1 and 6th term is -11​

Answers

Answered by Anonymous
1

Answer:

third term =1---(a+2d)--------------1

6th term=-11-----(a+5d)--------------2

by eliminate

-3d=12

d=-4

put d=-4in 1

a+2×-4=1

a-8=1

a=9

sn=n/2(2a +(n-1)d)

sn=32/2(2×9+31×-4)

=16(18-124)

=16(106)

=1696

Answered by Anonymous
0

Step-by-step explanation:

here comes the answer....

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