find the sum of 34+32+30+........+10
Answers
Answered by
5
That would be 44 + 44 + 44 + 44 + 44 + 44 + 22 = 44(6) + 22 = 286
Please mark brainliest or thanks if it helped :D
Answered by
8
heyy... here is your answer...
a= 34
a2=32
so d= a2-a
=32-34
d= -2
tn = 10
a+(n-1)d=10
34+(n-1)×-2=10
(n-1)×-2=10-34
(n-1)×-2= -24
(n-1) = -24/-2
(n-1)= 12
n= 12+1
n=13
.°.Sn = n/2{2a+(n-1)d}
= 13/2{2×34+(13-1)×-2}
= 13/2{68+(12)×-2}
=13/2(68-24)
= 13/2×44
=13×22
= 286.... hope this will help you....
plz mark as brainliest...
a= 34
a2=32
so d= a2-a
=32-34
d= -2
tn = 10
a+(n-1)d=10
34+(n-1)×-2=10
(n-1)×-2=10-34
(n-1)×-2= -24
(n-1) = -24/-2
(n-1)= 12
n= 12+1
n=13
.°.Sn = n/2{2a+(n-1)d}
= 13/2{2×34+(13-1)×-2}
= 13/2{68+(12)×-2}
=13/2(68-24)
= 13/2×44
=13×22
= 286.... hope this will help you....
plz mark as brainliest...
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