Question

Find the sum of 3x+8y - 3z, 2x -z –y, - 3z -4x -2y and z-5x+3y.​

Answer 1

Answer:

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Step-by-step explanation:

3x+8y+7z+4z−2x and 3y−4x+6z

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as =3x+8y+7z+4z−2x+3y−4x+6z

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as =3x+8y+7z+4z−2x+3y−4x+6zBy further calculation

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as =3x+8y+7z+4z−2x+3y−4x+6zBy further calculation =3x−2x−4x+8y+3y+7z+4z+6z

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as =3x+8y+7z+4z−2x+3y−4x+6zBy further calculation =3x−2x−4x+8y+3y+7z+4z+6zSo we get

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as =3x+8y+7z+4z−2x+3y−4x+6zBy further calculation =3x−2x−4x+8y+3y+7z+4z+6zSo we get =3x−6x+11y+17z

3x+8y+7z+4z−2x and 3y−4x+6zIt can be written as =3x+8y+7z+4z−2x+3y−4x+6zBy further calculation =3x−2x−4x+8y+3y+7z+4z+6zSo we get =3x−6x+11y+17z=−3x+11y+17z