find the sum of: 3x+8y+7z, 6x+4z-2x and 3y-4x+6z
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= ( 3x + 8y + 7z) + ( 6x + 4z - 2x ) + ( 3y - 4x + 6z ) [subtract 6x - 2x ]
= ( 3x + 8y + 7z) + ( 4x + 4z ) + (3y - 4x + 4z)
= 3x + 8y + 7z + 4x + 4z + 3y - 4x + 4z.
[arrange the no. in category ]
= 3x + 4x - 4x + 8y + 3y + 7z + 4z + 4z
= 3x + 11y + 15z
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