Question

Find the sum of 3x²-2xy+4y² and -x²+4xy-2y²​

Answer 1

Answer:

2$x^{2}$+2xy+2$y^{2}$

Step-by-step explanation:

Answer 2

Answer:

$(3^2-2xy+4y^2)+(-x^2+4xy-2y^2)$

$3x^2-2xy+4y^2-x^2+4xy-2y^2$

$(3x^2-x^2)+(-2xy+4xy)+(4y^2-2y^2)$

$2x^2+2xy+2y^2$