find the sum of 3x² + 2y², -x²-4y² and 6xy + 2x² - 3y², subtract 2x²+5y² - 4xy
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Step-by-step explanation:
(3x² + 2y² -x²-4y² + 6xy + 2x² - 3y² ) - ( 2x²+5y² - 4xy)
= ( 4x² - 5y² + 6xy) - ( 2x²+5y² - 4xy)
= 4x² - 5y² + 6xy - 2x²- 5y² + 4xy
= 2x² - 10 y² + 10 xy
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the answer is in the attachment
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