Question

Find the sum of -4 3/4+2 7/12

Answer 1

Given: Two fractions- $-4\frac{3}{4} \ and \ 2\frac{7}{12}$

To find: Sum of $-4\frac{3}{4} \ and \ 2\frac{7}{12}$

Solution:

The given fractions are in mixed fractional form. First we need to change them to improper fraction.

We get, $-4\frac{3}{4} = \frac{-19}{4}$ and $2\frac{7}{12} = \frac{31}{12}$

Now, we need to make their denominators same. So that it becomes easy to find the sum by just adding up the numerators.

LCM of their denominator 4 and 12 = 12

$\frac{-19}{4} = \frac{-19}{4}$ × $\frac{3}{3} = \frac{-57}{12}$ and $\frac{31}{12}$

Now,

∵ $-4\frac{3}{4} \ + \ 2\frac{7}{12} = \frac{-57}{12} \ + \ \frac{31}{12} = \frac{-57 \ + \ 31 }{12} = \frac{-26}{12} \ or \ \frac{-13}{6}$

Hence, sum of given expression is $\frac{-13}{6}.$

Answer 2

We must know:

$a\frac{b}{c}=\frac{a\times c+b}{c}$

Given:

$-4\frac{3}{4}+2\frac{7}{12}$

$\frac{-4\times 4+3}{4}+\frac{2 \times 12+7}{12}$

$\frac{-16+3}{4}+\frac{24+7}{12}$

$\frac{-13}{4}+\frac{31}{12}$

$\frac{-13\times 3+31}{12}$

$\frac{-39+31}{12}=\frac{-8}{12}$

$=\frac{-2}{3}$

The sum of $-4\frac{3}{4}+2\frac{7}{12}=\frac{-2}{3}$