find the sum of 40 terms of the series
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a=1
d=2-1=1
Sn=n/2 (2a+(n-1)d)
=40/2 (2 (1)+(40-1)1)
=20(2+39)
=20 (41)
=820
(D) is a correct answer
Hope it will help you
Aishwarya2003:
may I know in which progression is the question? ?
the answer is given as option B
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