FIND the sum of 4a-7ab+3b+12 and12a-9ab+5b-3
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Solution:
Given: (4a-7ab + 3b +12) and (12a - 9ab + 5b -3)
Now, subtracting (4a-7ab + 3b +12) from (12a - 9ab + 5b -3)
= (12a - 9ab + 5b - 3) - (4a - 7ab + 3b + 12)
=12a - 9ab + 5b - 3 - 4a + 7ab - 3b - 12
=8a + 2b - 2ab + 9
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