find the sum of 4a2 – 3ab + b2 , a2 – 3b2 and 4a2 −b2 +ab
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solution:-
=4a2- 1a2+ 4a2+ 3ab+ 1ab+ 1b2- 3b2- 3ab+1ab
Answer:- 7a2+ 4ab+ (-2b2) + (-2ab)
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