find the sum of 5+8+11+.....to 16 term's
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Answered by
1
Answer:
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Answered by
0
Answer:
440
Explanation:
In the given AP:
1st term = 5
And, Common difference = 8-5 = 11-8 = 3
No. of terms = 16
Then,
Sum of nth term = n/2 × {2a + (n-1)d}
= 16/2 × {2×5 + 15×3}
= 8 {10 + 45}
= 8 × 55
= 440
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